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TwEEk OutputPanel render FIRST and ONLY when button is pressed
How could you load up an output panel that doesnt bind at all UNTIL a button is pushed?
For example, I have the following
<apex:pageBlockButtons location="bottom">
<apex:commandButton value="Go" action="{!invokeService}" status="myStatus" rerender="myOutput" />
</apex:pageBlockButtons>
<apex:outputPanel id="myOutput">
<apex:actionStatus id="myStatus">
<apex:facet name="start">
Working...
</apex:facet>
<apex:facet name="stop">
<c:myComponent />
</apex:facet>
</apex:actionStatus>
</apex:outputPanel>
The component "myComponent" contains a datatable. This datatable appears to render the component on load, and bind the datatable on load.
But I dont want this behavior. I want it to first render ONLY when the button is pressed.
Any ideas?
I started trying to do a flag, where by [ if (flase) { dont bind, set true} ] so that on second click it would bind.
The tag was changed to
<apex:outputPanel rendered="{!ButtonClicked}" id="myOutput">
and the controller looks something like this
public class MyController {
Boolean clicked = false;
public MyController() {
clicked = false;
}
public PageReference invokeService() {
clicked = true;
return null;
}
public Boolean ButtonClicked(){
return clicked;
}
}
However when ever I click on the button I get the following error:
Attempt to de-reference a null object
An unexpected error has occurred. Your development organization has been notified.
I do not know if this will solve your problem, but I noticed an error in your code.
You have: <apex:outputPanel rendered="{!ButtonClicked}">.
Yet, your method is public Boolean ButtonClicked().
The return type of your method is a boolean, which means that it is not an action. Therefore, it is a property. To access it, your method name must be public Boolean getButtonClicked().
ApexGuy.
Modified code accordingly - this is not the problem.