Apex Code Development You need to sign in to do that
Don't have an account?
krish99 live agent connection error
Hi,
i am using following code when i used it means it showing an error message connection lost please check your connection, actually i created a my system admin as live agent when he login also it showing an error can any one help me.
MY CODE:::::::::
<html>
<head>
<title>
My title
</title>
<script type='text/javascript' src='https://c.la2c1.salesforceliveagent.com/content/g/deployment.js'></script>
</head>
<body>
Welcome to Live Agent
<a id="liveagent_button_online_573E0000000Ccuh" href="javascript://Chat" style="display: block;" onclick="liveagent.startChat('573E0000000Ccuh')"> Start live agent</a>
<script type='text/javascript'>
liveagent.init('https://d.la2c1.salesforceliveagent.com/chat', '572i0000000Qr3I', '00Di0000000d7eN');
</script>
<img id="liveagent_button_online_573i0000000Qskn" style="display: none; border: 0px none; cursor: pointer" onclick="liveagent.startChat('573i0000000Qskn')" src="https://esoftcenter-developer-edition.na15.force.com/resource/1377010559000/onlineimage" /><img id="liveagent_button_offline_573i0000000Qskn" style="display: none; border: 0px none; " src="https://esoftcenter-developer-edition.na15.force.com/resource/1377010588000/offlineimage" />
<script type="text/javascript">
if (!window._laq) { window._laq = []; }
window._laq.push(function(){liveagent.showWhenOnline('573i0000000Qskn', document.getElementById('liveagent_button_online_573i0000000Qskn'));
liveagent.showWhenOffline('573i0000000Qskn', document.getElementById('liveagent_button_offline_573i0000000Qskn'));
});</script>
</body>
</html>
i am using following code when i used it means it showing an error message connection lost please check your connection, actually i created a my system admin as live agent when he login also it showing an error can any one help me.
MY CODE:::::::::
<html>
<head>
<title>
My title
</title>
<script type='text/javascript' src='https://c.la2c1.salesforceliveagent.com/content/g/deployment.js'></script>
</head>
<body>
Welcome to Live Agent
<a id="liveagent_button_online_573E0000000Ccuh" href="javascript://Chat" style="display: block;" onclick="liveagent.startChat('573E0000000Ccuh')"> Start live agent</a>
<script type='text/javascript'>
liveagent.init('https://d.la2c1.salesforceliveagent.com/chat', '572i0000000Qr3I', '00Di0000000d7eN');
</script>
<img id="liveagent_button_online_573i0000000Qskn" style="display: none; border: 0px none; cursor: pointer" onclick="liveagent.startChat('573i0000000Qskn')" src="https://esoftcenter-developer-edition.na15.force.com/resource/1377010559000/onlineimage" /><img id="liveagent_button_offline_573i0000000Qskn" style="display: none; border: 0px none; " src="https://esoftcenter-developer-edition.na15.force.com/resource/1377010588000/offlineimage" />
<script type="text/javascript">
if (!window._laq) { window._laq = []; }
window._laq.push(function(){liveagent.showWhenOnline('573i0000000Qskn', document.getElementById('liveagent_button_online_573i0000000Qskn'));
liveagent.showWhenOffline('573i0000000Qskn', document.getElementById('liveagent_button_offline_573i0000000Qskn'));
});</script>
</body>
</html>
I am also having this issue... Wondering if there is an answer on how to resolve this yet?
Did you get solved your issue I'm also getting this issue please help..................;-)
Hi Mohan....
I'm also getting this issue please help..
How you both solved this?