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kotipalli srikanthkotipalli srikanth 

integer default value

Hello, Sfdc people.
I referred the following statement somewhere and found an ambiguity;
public return type methodname (integer n )
for (integer i=0; i<=n; i++)

The question is the "integer n" has not given any value, so how the for loop executes?
please explain me..
Your methodname method will be invoked from the other class or in the same class with the value of n being passed as a parameter 
please mark the answer as solved if it helps you 
arpit vijayvergiyaarpit vijayvergiya
This method will be called in this way new yourclassName().methodName(5);. You will pass parameter value in my case I passed 5. So the loop will execute 5 times.