Apex Code Development You need to sign in to do that
Don't have an account?
kotipalli srikanth integer default value
Hello, Sfdc people.
I referred the following statement somewhere and found an ambiguity;
public return type methodname (integer n )
{
for (integer i=0; i<=n; i++)
{
..............
}
}
The question is the "integer n" has not given any value, so how the for loop executes?
please explain me..
I referred the following statement somewhere and found an ambiguity;
public return type methodname (integer n )
{
for (integer i=0; i<=n; i++)
{
..............
}
}
The question is the "integer n" has not given any value, so how the for loop executes?
please explain me..
please mark the answer as solved if it helps you
This method will be called in this way new yourclassName().methodName(5);. You will pass parameter value in my case I passed 5. So the loop will execute 5 times.
Thanks,