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Kumar5Kumar5 

Error Message one Record Id in one line


Hi Team,
I am trying to catch  the exception message and record id, i  am  able to get both. But two different lines are gettting. Could you please help me to get in one line
 catch(DmlException e)          
        {
        Integer numErrors = e.getNumDml();
        for(Integer i=0;i<numErrors;i++) {
        ApexPages.Message msg = new ApexPages.Message(ApexPages.Severity.Error, e.getDmlId(i));
        ApexPages.addMessage(msg);
        // errorMsg += msg;
        errorMsg =  ' [e] ' + msg;
        newpage = null;
        }


Thanks,
Kumar
Raj VakatiRaj Vakati
Try this code
  
catch(DmlException e)          
        {
        Integer numErrors = e.getNumDml();
        for(Integer i=0;i<numErrors;i++) {
       // ApexPages.Message msg =;
        ApexPages.addMessage( new ApexPages.Message(ApexPages.Severity.Error, e.getDmlId(i)));
        // errorMsg += msg;
        errorMsg =  ' [e] ' + msg;
        newpage = null;
        }