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Oleg Nikitchuk Formula that displays photo
Hey everyone,
Need your help here! I am trying to make a formula that displays photo of car type(i have 3 car types: sedan, minivan, hatchback) if Type__c selected and isValidForRent is true. In other case it should sshow default text instead, smth like "no car available".
So far, I came up with this: IF(
AND(
NOT(ISBLANK(Type__c)),
isValidForRent = true
),
IMAGE(image_url, alternate_text),
"No car available"
)
but this solution doesn't work.
Please help me!
Need your help here! I am trying to make a formula that displays photo of car type(i have 3 car types: sedan, minivan, hatchback) if Type__c selected and isValidForRent is true. In other case it should sshow default text instead, smth like "no car available".
So far, I came up with this: IF(
AND(
NOT(ISBLANK(Type__c)),
isValidForRent = true
),
IMAGE(image_url, alternate_text),
"No car available"
)
but this solution doesn't work.
Please help me!
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