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Hariharan M 18Hariharan M 18 

sum Of OddValues from 1 to 10 using loops, can anyone write code ?

Best Answer chosen by Hariharan M 18
CharuDuttCharuDutt
Hii HariHaran
Try Below Code 
public class SumOfOddNumbers {
    public static void oddmethod(){
        integer SumOdd = 0;
        for(integer i=0;i<=10;i++){
            if( Math.mod(i,2) != 0){
                system.debug(i); 
                SumOdd+= i;
            }
        }
        system.debug(' SumOdd ==>   '+  SumOdd   );
    }
}
Please Mark It As Best Asnwer If It Helps
Thank You!

All Answers

Sai PraveenSai Praveen (Salesforce Developers) 
Hi Hariharan,

Please find the below code for sum of odd numbers between 1 to 10. You can execute this in anonomous window and get the result in logs.
  
Integer sum =0 ; 
for(Integer i = 0 ; i<=10 ;i++){
   if (Math.mod(i, 2) != 0) {
   sum= sum+i;
   }
    
}
System.debug('-->SUm'+sum);

Let me know if you face any issues.

If this solution helps, Please mark it as best answer.

Thanks,
CharuDuttCharuDutt
Hii HariHaran
Try Below Code 
public class SumOfOddNumbers {
    public static void oddmethod(){
        integer SumOdd = 0;
        for(integer i=0;i<=10;i++){
            if( Math.mod(i,2) != 0){
                system.debug(i); 
                SumOdd+= i;
            }
        }
        system.debug(' SumOdd ==>   '+  SumOdd   );
    }
}
Please Mark It As Best Asnwer If It Helps
Thank You!
This was selected as the best answer
Hariharan M 18Hariharan M 18
 solve the below expression by having n value and x value1x+2x+3x+....nx
 print the answer, can someone answer this?
Mohamed AhshanMohamed Ahshan

Hi bro, 
I can see that you are studying in AJ Skill an year ago 

Bro i have a question for you, Are you a Salesforce Developer now?