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srujith chintha 4srujith chintha 4 

print all of the positive integer from 1 to 100

  • Print out all positive integers from 1 to 100, inclusive and in order.
  • Print messages to standard output, matching the Sample Output below.
  • In the output, state whether each integer is ‘odd’ or ‘even’ in the output.
  • If the number is divisible by three, instead of stating that the number is odd or even, state that the number is ‘divisible by three’.
  • If the number is divisible by both two and three, instead of saying that the number is odd, even or divisible by three; state that the number is ‘divisible by two and three’.
  • Design the logic of the loop to be as efficient as possible, using the minimal number of operations to perform the required logic.
Best Answer chosen by srujith chintha 4
PriyaPriya (Salesforce Developers) 
Hey Srujith,

Please try below :-  
for(Integer i=1;i<=100;i++){
    Integer result = math.mod(i,2);
    if(result == 0){
        System.debug(i);
    }
}

Please mark it as the best answer if it resolves your issue.

For more solution, refer this :-
https://developer.salesforce.com/forums/?id=9062I000000gCmpQAE

Thanks

All Answers

PriyaPriya (Salesforce Developers) 
Hey Srujith,

Please try below :-  
for(Integer i=1;i<=100;i++){
    Integer result = math.mod(i,2);
    if(result == 0){
        System.debug(i);
    }
}

Please mark it as the best answer if it resolves your issue.

For more solution, refer this :-
https://developer.salesforce.com/forums/?id=9062I000000gCmpQAE

Thanks
This was selected as the best answer
srujith chintha 4srujith chintha 4
I have done using this code .but thank u for ur help
public class printIntegers {
    public static void printIntegersWithOddOrEven(){
        for(integer i=1;i<=100;i++){
            if((math.mod(i, 2))==0 && (math.mod(i, 3))==0){
                system.debug(i+':is divisible by 2 and 3');
            }
            else if((math.mod(i, 3))==0){
                system.debug(i+': is divisible by  3');
            }
            else {
                if((math.mod(i, 2))==0){
                    system.debug(i+': is even');
                }
                else{
                    system.debug(i+': is odd');
                }
            }
        }
    }