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Hema Yejju i want a custom object field to provide input on record page while i am clicking quick action button
@AuraEnabled(cacheable=true)
public static Map<Id,String> getCaseextCd(Id recordId){
List<Case> csext = new List<Case>();
List<object__c> csExList=new List<object__c>();
Map<Id,String> caseIdCommentforsales=new Map<Id,String>();
csext=[Select Id, (SELECT Case__c, Comment_for_Sales__c,Approver__c FROM object__r FROM Case WHERE Id=:recordId];
System.debug('csext :::'+csext);
for(Case c:csext){
if(!c.object__r.isEmpty()){
csExList.add(c.object__r);
}
}
for (object__c csEx:csExList){
caseIdCommentforsales.put(csEx.Case__c,csEx.Comment_for_Sales__c );
system.debug('caseIdCommentforsales'+caseIdCommentforsales);
}
return caseIdCommentforsales;
}
LWC:
@wire(getCaseextCd, { recordId: '$recordId', fields: [NAME_FIELD1] })
cons(result) {
this.caseCommentr = result;
if (result.error) {
this.caseCommentr = undefined;
}
};
_______________________________________________
My LWC was incorrect and i am unable to write the lwc how to display the field on Click of the quick action button and how to stroe the input given for the field on the record for the particualr Objetc.field
public static Map<Id,String> getCaseextCd(Id recordId){
List<Case> csext = new List<Case>();
List<object__c> csExList=new List<object__c>();
Map<Id,String> caseIdCommentforsales=new Map<Id,String>();
csext=[Select Id, (SELECT Case__c, Comment_for_Sales__c,Approver__c FROM object__r FROM Case WHERE Id=:recordId];
System.debug('csext :::'+csext);
for(Case c:csext){
if(!c.object__r.isEmpty()){
csExList.add(c.object__r);
}
}
for (object__c csEx:csExList){
caseIdCommentforsales.put(csEx.Case__c,csEx.Comment_for_Sales__c );
system.debug('caseIdCommentforsales'+caseIdCommentforsales);
}
return caseIdCommentforsales;
}
LWC:
@wire(getCaseextCd, { recordId: '$recordId', fields: [NAME_FIELD1] })
cons(result) {
this.caseCommentr = result;
if (result.error) {
this.caseCommentr = undefined;
}
};
_______________________________________________
My LWC was incorrect and i am unable to write the lwc how to display the field on Click of the quick action button and how to stroe the input given for the field on the record for the particualr Objetc.field
Please follow below url:-
https://www.apexhours.com/call-apex-method-from-lightning-web-components/
if you need any assistanse, Please let me know!!
Kindly mark my solution as the best answer if it helps you.
Thanks
Mukesh
i an trying to display one custom object field using <lightning-record-edit-form> inside of </lightning-quick-action-panel> to display that field on my button click of quick action .
but i am not getting my custom object field on UI.
could you pleasse let me know what was the mistake
<lightning-record-edit-form
object-api-name={MY_CUSTOM_OBJECT}
record-id={recordIdcaseext}
onsuccess={handleSuccess}
>
import MY_CUSTOM_OBJECT from '@salesforce/schema/Case_Ext__c';