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noedskov Linking a lead to a campaign
Hi all,
We use the API for various tasks and one of them is to create leads within salesforce which are generated from our website.
Now, a sub-set of these leads we want to make part of specific campaign and below I have included some example code.
No doubt I get the correct campaign but when I create a new lead and set the campaign (see code below) I get the following error message: Invalid foreign key relationship name Campaign
Any suggestions?
Cheers.
/Søren Nødskov Hansen
We use the API for various tasks and one of them is to create leads within salesforce which are generated from our website.
Now, a sub-set of these leads we want to make part of specific campaign and below I have included some example code.
Code:
String[] campaignIds = {"70120000000AFKy"}; //Campaign Id for Free Website Trial
SObject[] campaigns = stub.retrieve("Name", "Campaign ID", campaignIds); //Retrieve matching objects (should only be one)
Campaign campaign = null;
for(int x = 0; x < campaigns.length; x++) { //Loop through objects found
campaign = (Campaign)campaigns[x];
System.out.println("Got campaign: " + campaign.getName() + " with id: " + campaign.getId()); //Print name and id of campaign
}No doubt I get the correct campaign but when I create a new lead and set the campaign (see code below) I get the following error message: Invalid foreign key relationship name Campaign
Code:
lead.setCampaign(campaign);
Any suggestions?
Cheers.
/Søren Nødskov Hansen
Thanks for your input - it helped me a lot!
Just in case others are wondering how I ended up doing it here is that part of my code:
//Create a new lead Lead lead = new Lead(); lead.setCompany("my company"); ... ... // Save the lead and verify result Lead[] leads = {lead}; SaveResult[] results = stub.create(leads); SaveResult result = null; for(int i = 0; i < results.length; i++) { result = results[i]; if(result.isSuccess()) { System.out.println("Lead created with id: " + result.getId()); CampaignMember member = new CampaignMember(); member.setCampaignId("70120000000AFKy"); member.setLeadId(result.getId()); // Save the member and verify result CampaignMember[] members = {member}; SaveResult[] memberResults = stub.create(members); SaveResult memberResult = null; for(int j = 0; j < memberResults.length; j++) { memberResult = memberResults[j]; if(memberResult.isSuccess()) { System.out.println("CampaignMember created with id: " + memberResult.getId()); } else { System.out.println("Failed creating CampaignMember: " + memberResult.getErrors(j).getMessage()); } } } else { System.out.println("Failed creating lead: " + result.getErrors(i).getMessage()); } }It seemed that just setting the campaign id and the lead id on the campaign member was sufficient in order to map the two objects.
/Søren Nødskov Hansen
All Answers
Thanks for your input - it helped me a lot!
Just in case others are wondering how I ended up doing it here is that part of my code:
//Create a new lead Lead lead = new Lead(); lead.setCompany("my company"); ... ... // Save the lead and verify result Lead[] leads = {lead}; SaveResult[] results = stub.create(leads); SaveResult result = null; for(int i = 0; i < results.length; i++) { result = results[i]; if(result.isSuccess()) { System.out.println("Lead created with id: " + result.getId()); CampaignMember member = new CampaignMember(); member.setCampaignId("70120000000AFKy"); member.setLeadId(result.getId()); // Save the member and verify result CampaignMember[] members = {member}; SaveResult[] memberResults = stub.create(members); SaveResult memberResult = null; for(int j = 0; j < memberResults.length; j++) { memberResult = memberResults[j]; if(memberResult.isSuccess()) { System.out.println("CampaignMember created with id: " + memberResult.getId()); } else { System.out.println("Failed creating CampaignMember: " + memberResult.getErrors(j).getMessage()); } } } else { System.out.println("Failed creating lead: " + result.getErrors(i).getMessage()); } }It seemed that just setting the campaign id and the lead id on the campaign member was sufficient in order to map the two objects.
/Søren Nødskov Hansen