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For "each" loop follows the order as for (integer i=0; i< xx, i++) ?

Integer[] arr = new Integer[] {3, 31,6,9};

loop 1

for (Integer tmp: arr) {

}

lopp2

for (Integer i=0; i < arr.size();i++) {

Integer tmp = arr[i]

}

Will those 2 loop follow the same order when iterating the array ?

Best Answer chosen by Admin (Salesforce Developers)

logontokartik
Yes. when you define an array in that format, its nothing but a list collection, which is ordered.

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